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5x^2+43x+66=0
a = 5; b = 43; c = +66;
Δ = b2-4ac
Δ = 432-4·5·66
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-23}{2*5}=\frac{-66}{10} =-6+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+23}{2*5}=\frac{-20}{10} =-2 $
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